Solve 10x + 12 = −38

The solution of 10x + 12 = −38 is x = -5.

10x + 12 = -38\ \Rightarrow\ x = -5

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The lines y = 10x + 12 and y = -38 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$10x + 12 = -38$
2
Subtract 12 from both sides:
$10x + 12 - 12 = -38 - 12 \ \Rightarrow\ 10x = -50$
3
Divide both sides by 10:
$\frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5$
4
Check: put x = -5 back into the equation.
$10\cdot(-5) + 12 = -50 + 12 = -38 \checkmark$

LaTeX source of the formulas on this page

\[ 10x + 12 = -38\ \Rightarrow\ x = -5 \]
\[ 10x + 12 = -38 \]
\[ 10x + 12 - 12 = -38 - 12 \ \Rightarrow\ 10x = -50 \]
\[ \frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5 \]
\[ 10\cdot(-5) + 12 = -50 + 12 = -38 \checkmark \]

Trying values of x in 10x + 12 = −38

x	10x + 12	Equals -38?
-7	-58	no
-6	-48	no
-5	-38	yes
-4	-28	no
-3	-18	no

Questions

What is x in 10x + 12 = −38?

The solution of 10x + 12 = −38 is x = -5.

How do you solve 10x + 12 = −38?

Subtract 12 from both sides to get 10x = -50, then divide both sides by 10 to get x = -5.

How do I check the answer?

Replace x by -5: 10(-5) + 12 = -38, which is -38.

Solve 10x + 12 = −38

How to work it out

Trying values of x in 10x + 12 = −38

Questions

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