Solve 10x + 12 = ā48
The solution of 10x + 12 = ā48 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 12 = -48\ \Rightarrow\ x = -6 \]
\[ 10x + 12 = -48 \]
\[ 10x + 12 - 12 = -48 - 12 \ \Rightarrow\ 10x = -60 \]
\[ \frac{10x}{10} = \frac{-60}{10} \ \Rightarrow\ x = -6 \]
\[ 10\cdot(-6) + 12 = -60 + 12 = -48 \checkmark \]Trying values of x in 10x + 12 = ā48
| x | 10x + 12 | Equals -48? |
|---|---|---|
| -8 | -68 | no |
| -7 | -58 | no |
| -6 | -48 | yes |
| -5 | -38 | no |
| -4 | -28 | no |
Questions
What is x in 10x + 12 = ā48?
The solution of 10x + 12 = ā48 is x = -6.
How do you solve 10x + 12 = ā48?
Subtract 12 from both sides to get 10x = -60, then divide both sides by 10 to get x = -6.
How do I check the answer?
Replace x by -6: 10(-6) + 12 = -48, which is -48.