Solve 10x + 12 = ā58
The solution of 10x + 12 = ā58 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 12 = -58\ \Rightarrow\ x = -7 \]
\[ 10x + 12 = -58 \]
\[ 10x + 12 - 12 = -58 - 12 \ \Rightarrow\ 10x = -70 \]
\[ \frac{10x}{10} = \frac{-70}{10} \ \Rightarrow\ x = -7 \]
\[ 10\cdot(-7) + 12 = -70 + 12 = -58 \checkmark \]Trying values of x in 10x + 12 = ā58
| x | 10x + 12 | Equals -58? |
|---|---|---|
| -9 | -78 | no |
| -8 | -68 | no |
| -7 | -58 | yes |
| -6 | -48 | no |
| -5 | -38 | no |
Questions
What is x in 10x + 12 = ā58?
The solution of 10x + 12 = ā58 is x = -7.
How do you solve 10x + 12 = ā58?
Subtract 12 from both sides to get 10x = -70, then divide both sides by 10 to get x = -7.
How do I check the answer?
Replace x by -7: 10(-7) + 12 = -58, which is -58.