Solve 11x + 12 = ā43
The solution of 11x + 12 = ā43 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 12 = -43\ \Rightarrow\ x = -5 \]
\[ 11x + 12 = -43 \]
\[ 11x + 12 - 12 = -43 - 12 \ \Rightarrow\ 11x = -55 \]
\[ \frac{11x}{11} = \frac{-55}{11} \ \Rightarrow\ x = -5 \]
\[ 11\cdot(-5) + 12 = -55 + 12 = -43 \checkmark \]Trying values of x in 11x + 12 = ā43
| x | 11x + 12 | Equals -43? |
|---|---|---|
| -7 | -65 | no |
| -6 | -54 | no |
| -5 | -43 | yes |
| -4 | -32 | no |
| -3 | -21 | no |
Questions
What is x in 11x + 12 = ā43?
The solution of 11x + 12 = ā43 is x = -5.
How do you solve 11x + 12 = ā43?
Subtract 12 from both sides to get 11x = -55, then divide both sides by 11 to get x = -5.
How do I check the answer?
Replace x by -5: 11(-5) + 12 = -43, which is -43.