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Solve 10x āˆ’ 12 = āˆ’62

The solution of 10x āˆ’ 12 = āˆ’62 is x = -5.

The lines y = 10x āˆ’ 12 and y = -62 meet at x = -5-10-8-6-4-2-120-100-80-60-40-20x = -5y = 10x āˆ’ 12y = -62
The lines y = 10x āˆ’ 12 and y = -62 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’12=āˆ’6210x - 12 = -62
  2. 2

    Add 12 to both sides:

    10xāˆ’12+12=āˆ’62+12 ⇒ 10x=āˆ’5010x - 12 + 12 = -62 + 12 \ \Rightarrow\ 10x = -50
  3. 3

    Divide both sides by 10:

    10x10=āˆ’5010 ⇒ x=āˆ’5\frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    10ā‹…(āˆ’5)āˆ’12=āˆ’50āˆ’12=āˆ’62āœ“10\cdot(-5) - 12 = -50 - 12 = -62 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 12 = -62\ \Rightarrow\ x = -5 \]
\[ 10x - 12 = -62 \]
\[ 10x - 12 + 12 = -62 + 12 \ \Rightarrow\ 10x = -50 \]
\[ \frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5 \]
\[ 10\cdot(-5) - 12 = -50 - 12 = -62 \checkmark \]

Trying values of x in 10x āˆ’ 12 = āˆ’62

x10x āˆ’ 12Equals -62?
-7-82no
-6-72no
-5-62yes
-4-52no
-3-42no

Questions

What is x in 10x āˆ’ 12 = āˆ’62?

The solution of 10x āˆ’ 12 = āˆ’62 is x = -5.

How do you solve 10x āˆ’ 12 = āˆ’62?

Add 12 to both sides to get 10x = -50, then divide both sides by 10 to get x = -5.

How do I check the answer?

Replace x by -5: 10(-5) āˆ’ 12 = -62, which is -62.

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    Solve 10x āˆ’ 12 = āˆ’62: x = -5 (steps and check) | WordGPT