Solve 10x + 12 = ā28
The solution of 10x + 12 = ā28 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 12 = -28\ \Rightarrow\ x = -4 \]
\[ 10x + 12 = -28 \]
\[ 10x + 12 - 12 = -28 - 12 \ \Rightarrow\ 10x = -40 \]
\[ \frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4 \]
\[ 10\cdot(-4) + 12 = -40 + 12 = -28 \checkmark \]Trying values of x in 10x + 12 = ā28
| x | 10x + 12 | Equals -28? |
|---|---|---|
| -6 | -48 | no |
| -5 | -38 | no |
| -4 | -28 | yes |
| -3 | -18 | no |
| -2 | -8 | no |
Questions
What is x in 10x + 12 = ā28?
The solution of 10x + 12 = ā28 is x = -4.
How do you solve 10x + 12 = ā28?
Subtract 12 from both sides to get 10x = -40, then divide both sides by 10 to get x = -4.
How do I check the answer?
Replace x by -4: 10(-4) + 12 = -28, which is -28.