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Solve 10x + 12 = āˆ’28

The solution of 10x + 12 = āˆ’28 is x = -4.

The lines y = 10x + 12 and y = -28 meet at x = -4-10-8-6-4-22-100-80-60-40-202040x = -4y = 10x + 12y = -28
The lines y = 10x + 12 and y = -28 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+12=āˆ’2810x + 12 = -28
  2. 2

    Subtract 12 from both sides:

    10x+12āˆ’12=āˆ’28āˆ’12 ⇒ 10x=āˆ’4010x + 12 - 12 = -28 - 12 \ \Rightarrow\ 10x = -40
  3. 3

    Divide both sides by 10:

    10x10=āˆ’4010 ⇒ x=āˆ’4\frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    10ā‹…(āˆ’4)+12=āˆ’40+12=āˆ’28āœ“10\cdot(-4) + 12 = -40 + 12 = -28 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 12 = -28\ \Rightarrow\ x = -4 \]
\[ 10x + 12 = -28 \]
\[ 10x + 12 - 12 = -28 - 12 \ \Rightarrow\ 10x = -40 \]
\[ \frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4 \]
\[ 10\cdot(-4) + 12 = -40 + 12 = -28 \checkmark \]

Trying values of x in 10x + 12 = āˆ’28

x10x + 12Equals -28?
-6-48no
-5-38no
-4-28yes
-3-18no
-2-8no

Questions

What is x in 10x + 12 = āˆ’28?

The solution of 10x + 12 = āˆ’28 is x = -4.

How do you solve 10x + 12 = āˆ’28?

Subtract 12 from both sides to get 10x = -40, then divide both sides by 10 to get x = -4.

How do I check the answer?

Replace x by -4: 10(-4) + 12 = -28, which is -28.

Similar equations

    Solve 10x + 12 = āˆ’28: x = -4 (steps and check) | WordGPT