Solve 2x + 1 = ā3
The solution of 2x + 1 = ā3 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 1 = -3\ \Rightarrow\ x = -2 \]
\[ 2x + 1 = -3 \]
\[ 2x + 1 - 1 = -3 - 1 \ \Rightarrow\ 2x = -4 \]
\[ \frac{2x}{2} = \frac{-4}{2} \ \Rightarrow\ x = -2 \]
\[ 2\cdot(-2) + 1 = -4 + 1 = -3 \checkmark \]Trying values of x in 2x + 1 = ā3
| x | 2x + 1 | Equals -3? |
|---|---|---|
| -4 | -7 | no |
| -3 | -5 | no |
| -2 | -3 | yes |
| -1 | -1 | no |
| 0 | 1 | no |
Questions
What is x in 2x + 1 = ā3?
The solution of 2x + 1 = ā3 is x = -2.
How do you solve 2x + 1 = ā3?
Subtract 1 from both sides to get 2x = -4, then divide both sides by 2 to get x = -2.
How do I check the answer?
Replace x by -2: 2(-2) + 1 = -3, which is -3.