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Solve 3x + 1 = āˆ’5

The solution of 3x + 1 = āˆ’5 is x = -2.

The lines y = 3x + 1 and y = -5 meet at x = -2-8-6-4-224-25-20-15-10-551015x = -2y = 3x + 1y = -5
The lines y = 3x + 1 and y = -5 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+1=āˆ’53x + 1 = -5
  2. 2

    Subtract 1 from both sides:

    3x+1āˆ’1=āˆ’5āˆ’1 ⇒ 3x=āˆ’63x + 1 - 1 = -5 - 1 \ \Rightarrow\ 3x = -6
  3. 3

    Divide both sides by 3:

    3x3=āˆ’63 ⇒ x=āˆ’2\frac{3x}{3} = \frac{-6}{3} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    3ā‹…(āˆ’2)+1=āˆ’6+1=āˆ’5āœ“3\cdot(-2) + 1 = -6 + 1 = -5 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 1 = -5\ \Rightarrow\ x = -2 \]
\[ 3x + 1 = -5 \]
\[ 3x + 1 - 1 = -5 - 1 \ \Rightarrow\ 3x = -6 \]
\[ \frac{3x}{3} = \frac{-6}{3} \ \Rightarrow\ x = -2 \]
\[ 3\cdot(-2) + 1 = -6 + 1 = -5 \checkmark \]

Trying values of x in 3x + 1 = āˆ’5

x3x + 1Equals -5?
-4-11no
-3-8no
-2-5yes
-1-2no
01no

Questions

What is x in 3x + 1 = āˆ’5?

The solution of 3x + 1 = āˆ’5 is x = -2.

How do you solve 3x + 1 = āˆ’5?

Subtract 1 from both sides to get 3x = -6, then divide both sides by 3 to get x = -2.

How do I check the answer?

Replace x by -2: 3(-2) + 1 = -5, which is -5.

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    Solve 3x + 1 = āˆ’5: x = -2 (steps and check) | WordGPT