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Solve 2x āˆ’ 1 = āˆ’5

The solution of 2x āˆ’ 1 = āˆ’5 is x = -2.

The lines y = 2x āˆ’ 1 and y = -5 meet at x = -2-8-6-4-224-15-10-55x = -2y = 2x āˆ’ 1y = -5
The lines y = 2x āˆ’ 1 and y = -5 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’1=āˆ’52x - 1 = -5
  2. 2

    Add 1 to both sides:

    2xāˆ’1+1=āˆ’5+1 ⇒ 2x=āˆ’42x - 1 + 1 = -5 + 1 \ \Rightarrow\ 2x = -4
  3. 3

    Divide both sides by 2:

    2x2=āˆ’42 ⇒ x=āˆ’2\frac{2x}{2} = \frac{-4}{2} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    2ā‹…(āˆ’2)āˆ’1=āˆ’4āˆ’1=āˆ’5āœ“2\cdot(-2) - 1 = -4 - 1 = -5 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 1 = -5\ \Rightarrow\ x = -2 \]
\[ 2x - 1 = -5 \]
\[ 2x - 1 + 1 = -5 + 1 \ \Rightarrow\ 2x = -4 \]
\[ \frac{2x}{2} = \frac{-4}{2} \ \Rightarrow\ x = -2 \]
\[ 2\cdot(-2) - 1 = -4 - 1 = -5 \checkmark \]

Trying values of x in 2x āˆ’ 1 = āˆ’5

x2x āˆ’ 1Equals -5?
-4-9no
-3-7no
-2-5yes
-1-3no
0-1no

Questions

What is x in 2x āˆ’ 1 = āˆ’5?

The solution of 2x āˆ’ 1 = āˆ’5 is x = -2.

How do you solve 2x āˆ’ 1 = āˆ’5?

Add 1 to both sides to get 2x = -4, then divide both sides by 2 to get x = -2.

How do I check the answer?

Replace x by -2: 2(-2) āˆ’ 1 = -5, which is -5.

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    Solve 2x āˆ’ 1 = āˆ’5: x = -2 (steps and check) | WordGPT