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Solve 2x + 1 = āˆ’1

The solution of 2x + 1 = āˆ’1 is x = -1.

The lines y = 2x + 1 and y = -1 meet at x = -1-6-4-224-15-10-5510x = -1y = 2x + 1y = -1
The lines y = 2x + 1 and y = -1 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+1=āˆ’12x + 1 = -1
  2. 2

    Subtract 1 from both sides:

    2x+1āˆ’1=āˆ’1āˆ’1 ⇒ 2x=āˆ’22x + 1 - 1 = -1 - 1 \ \Rightarrow\ 2x = -2
  3. 3

    Divide both sides by 2:

    2x2=āˆ’22 ⇒ x=āˆ’1\frac{2x}{2} = \frac{-2}{2} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    2ā‹…(āˆ’1)+1=āˆ’2+1=āˆ’1āœ“2\cdot(-1) + 1 = -2 + 1 = -1 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 1 = -1\ \Rightarrow\ x = -1 \]
\[ 2x + 1 = -1 \]
\[ 2x + 1 - 1 = -1 - 1 \ \Rightarrow\ 2x = -2 \]
\[ \frac{2x}{2} = \frac{-2}{2} \ \Rightarrow\ x = -1 \]
\[ 2\cdot(-1) + 1 = -2 + 1 = -1 \checkmark \]

Trying values of x in 2x + 1 = āˆ’1

x2x + 1Equals -1?
-3-5no
-2-3no
-1-1yes
01no
13no

Questions

What is x in 2x + 1 = āˆ’1?

The solution of 2x + 1 = āˆ’1 is x = -1.

How do you solve 2x + 1 = āˆ’1?

Subtract 1 from both sides to get 2x = -2, then divide both sides by 2 to get x = -1.

How do I check the answer?

Replace x by -1: 2(-1) + 1 = -1, which is -1.

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    Solve 2x + 1 = āˆ’1: x = -1 (steps and check) | WordGPT