Solve 11x ā 5 = ā38
The solution of 11x ā 5 = ā38 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 5 to both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 11x - 5 = -38\ \Rightarrow\ x = -3 \]
\[ 11x - 5 = -38 \]
\[ 11x - 5 + 5 = -38 + 5 \ \Rightarrow\ 11x = -33 \]
\[ \frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3 \]
\[ 11\cdot(-3) - 5 = -33 - 5 = -38 \checkmark \]Trying values of x in 11x ā 5 = ā38
| x | 11x ā 5 | Equals -38? |
|---|---|---|
| -5 | -60 | no |
| -4 | -49 | no |
| -3 | -38 | yes |
| -2 | -27 | no |
| -1 | -16 | no |
Questions
What is x in 11x ā 5 = ā38?
The solution of 11x ā 5 = ā38 is x = -3.
How do you solve 11x ā 5 = ā38?
Add 5 to both sides to get 11x = -33, then divide both sides by 11 to get x = -3.
How do I check the answer?
Replace x by -3: 11(-3) ā 5 = -38, which is -38.