Solve 11x ā 5 = ā27
The solution of 11x ā 5 = ā27 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 5 to both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 11x - 5 = -27\ \Rightarrow\ x = -2 \]
\[ 11x - 5 = -27 \]
\[ 11x - 5 + 5 = -27 + 5 \ \Rightarrow\ 11x = -22 \]
\[ \frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2 \]
\[ 11\cdot(-2) - 5 = -22 - 5 = -27 \checkmark \]Trying values of x in 11x ā 5 = ā27
| x | 11x ā 5 | Equals -27? |
|---|---|---|
| -4 | -49 | no |
| -3 | -38 | no |
| -2 | -27 | yes |
| -1 | -16 | no |
| 0 | -5 | no |
Questions
What is x in 11x ā 5 = ā27?
The solution of 11x ā 5 = ā27 is x = -2.
How do you solve 11x ā 5 = ā27?
Add 5 to both sides to get 11x = -22, then divide both sides by 11 to get x = -2.
How do I check the answer?
Replace x by -2: 11(-2) ā 5 = -27, which is -27.