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Solve 12x āˆ’ 5 = āˆ’41

The solution of 12x āˆ’ 5 = āˆ’41 is x = -3.

The lines y = 12x āˆ’ 5 and y = -41 meet at x = -3-8-6-4-22-120-100-80-60-40-202040x = -3y = 12x āˆ’ 5y = -41
The lines y = 12x āˆ’ 5 and y = -41 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’5=āˆ’4112x - 5 = -41
  2. 2

    Add 5 to both sides:

    12xāˆ’5+5=āˆ’41+5 ⇒ 12x=āˆ’3612x - 5 + 5 = -41 + 5 \ \Rightarrow\ 12x = -36
  3. 3

    Divide both sides by 12:

    12x12=āˆ’3612 ⇒ x=āˆ’3\frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    12ā‹…(āˆ’3)āˆ’5=āˆ’36āˆ’5=āˆ’41āœ“12\cdot(-3) - 5 = -36 - 5 = -41 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 5 = -41\ \Rightarrow\ x = -3 \]
\[ 12x - 5 = -41 \]
\[ 12x - 5 + 5 = -41 + 5 \ \Rightarrow\ 12x = -36 \]
\[ \frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3 \]
\[ 12\cdot(-3) - 5 = -36 - 5 = -41 \checkmark \]

Trying values of x in 12x āˆ’ 5 = āˆ’41

x12x āˆ’ 5Equals -41?
-5-65no
-4-53no
-3-41yes
-2-29no
-1-17no

Questions

What is x in 12x āˆ’ 5 = āˆ’41?

The solution of 12x āˆ’ 5 = āˆ’41 is x = -3.

How do you solve 12x āˆ’ 5 = āˆ’41?

Add 5 to both sides to get 12x = -36, then divide both sides by 12 to get x = -3.

How do I check the answer?

Replace x by -3: 12(-3) āˆ’ 5 = -41, which is -41.

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    Solve 12x āˆ’ 5 = āˆ’41: x = -3 (steps and check) | WordGPT