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Solve 12x āˆ’ 5 = āˆ’53

The solution of 12x āˆ’ 5 = āˆ’53 is x = -4.

The lines y = 12x āˆ’ 5 and y = -53 meet at x = -4-10-8-6-4-22-120-100-80-60-40-2020x = -4y = 12x āˆ’ 5y = -53
The lines y = 12x āˆ’ 5 and y = -53 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’5=āˆ’5312x - 5 = -53
  2. 2

    Add 5 to both sides:

    12xāˆ’5+5=āˆ’53+5 ⇒ 12x=āˆ’4812x - 5 + 5 = -53 + 5 \ \Rightarrow\ 12x = -48
  3. 3

    Divide both sides by 12:

    12x12=āˆ’4812 ⇒ x=āˆ’4\frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    12ā‹…(āˆ’4)āˆ’5=āˆ’48āˆ’5=āˆ’53āœ“12\cdot(-4) - 5 = -48 - 5 = -53 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 5 = -53\ \Rightarrow\ x = -4 \]
\[ 12x - 5 = -53 \]
\[ 12x - 5 + 5 = -53 + 5 \ \Rightarrow\ 12x = -48 \]
\[ \frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4 \]
\[ 12\cdot(-4) - 5 = -48 - 5 = -53 \checkmark \]

Trying values of x in 12x āˆ’ 5 = āˆ’53

x12x āˆ’ 5Equals -53?
-6-77no
-5-65no
-4-53yes
-3-41no
-2-29no

Questions

What is x in 12x āˆ’ 5 = āˆ’53?

The solution of 12x āˆ’ 5 = āˆ’53 is x = -4.

How do you solve 12x āˆ’ 5 = āˆ’53?

Add 5 to both sides to get 12x = -48, then divide both sides by 12 to get x = -4.

How do I check the answer?

Replace x by -4: 12(-4) āˆ’ 5 = -53, which is -53.

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    Solve 12x āˆ’ 5 = āˆ’53: x = -4 (steps and check) | WordGPT