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Solve 11x + 5 = āˆ’28

The solution of 11x + 5 = āˆ’28 is x = -3.

The lines y = 11x + 5 and y = -28 meet at x = -3-8-6-4-22-100-80-60-40-202040x = -3y = 11x + 5y = -28
The lines y = 11x + 5 and y = -28 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+5=āˆ’2811x + 5 = -28
  2. 2

    Subtract 5 from both sides:

    11x+5āˆ’5=āˆ’28āˆ’5 ⇒ 11x=āˆ’3311x + 5 - 5 = -28 - 5 \ \Rightarrow\ 11x = -33
  3. 3

    Divide both sides by 11:

    11x11=āˆ’3311 ⇒ x=āˆ’3\frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    11ā‹…(āˆ’3)+5=āˆ’33+5=āˆ’28āœ“11\cdot(-3) + 5 = -33 + 5 = -28 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 5 = -28\ \Rightarrow\ x = -3 \]
\[ 11x + 5 = -28 \]
\[ 11x + 5 - 5 = -28 - 5 \ \Rightarrow\ 11x = -33 \]
\[ \frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3 \]
\[ 11\cdot(-3) + 5 = -33 + 5 = -28 \checkmark \]

Trying values of x in 11x + 5 = āˆ’28

x11x + 5Equals -28?
-5-50no
-4-39no
-3-28yes
-2-17no
-1-6no

Questions

What is x in 11x + 5 = āˆ’28?

The solution of 11x + 5 = āˆ’28 is x = -3.

How do you solve 11x + 5 = āˆ’28?

Subtract 5 from both sides to get 11x = -33, then divide both sides by 11 to get x = -3.

How do I check the answer?

Replace x by -3: 11(-3) + 5 = -28, which is -28.

Similar equations

    Solve 11x + 5 = āˆ’28: x = -3 (steps and check) | WordGPT