Solve 10x + 2 = −38

The solution of 10x + 2 = −38 is x = -4.

10x + 2 = -38\ \Rightarrow\ x = -4

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The lines y = 10x + 2 and y = -38 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$10x + 2 = -38$
2
Subtract 2 from both sides:
$10x + 2 - 2 = -38 - 2 \ \Rightarrow\ 10x = -40$
3
Divide both sides by 10:
$\frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4$
4
Check: put x = -4 back into the equation.
$10\cdot(-4) + 2 = -40 + 2 = -38 \checkmark$

LaTeX source of the formulas on this page

\[ 10x + 2 = -38\ \Rightarrow\ x = -4 \]
\[ 10x + 2 = -38 \]
\[ 10x + 2 - 2 = -38 - 2 \ \Rightarrow\ 10x = -40 \]
\[ \frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4 \]
\[ 10\cdot(-4) + 2 = -40 + 2 = -38 \checkmark \]

Trying values of x in 10x + 2 = −38

x	10x + 2	Equals -38?
-6	-58	no
-5	-48	no
-4	-38	yes
-3	-28	no
-2	-18	no

Questions

What is x in 10x + 2 = −38?

The solution of 10x + 2 = −38 is x = -4.

How do you solve 10x + 2 = −38?

Subtract 2 from both sides to get 10x = -40, then divide both sides by 10 to get x = -4.

How do I check the answer?

Replace x by -4: 10(-4) + 2 = -38, which is -38.

Solve 10x + 2 = −38

How to work it out

Trying values of x in 10x + 2 = −38

Questions

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