Solve 10x + 2 = −28

The solution of 10x + 2 = −28 is x = -3.

10x + 2 = -28\ \Rightarrow\ x = -3

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The lines y = 10x + 2 and y = -28 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$10x + 2 = -28$
2
Subtract 2 from both sides:
$10x + 2 - 2 = -28 - 2 \ \Rightarrow\ 10x = -30$
3
Divide both sides by 10:
$\frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3$
4
Check: put x = -3 back into the equation.
$10\cdot(-3) + 2 = -30 + 2 = -28 \checkmark$

LaTeX source of the formulas on this page

\[ 10x + 2 = -28\ \Rightarrow\ x = -3 \]
\[ 10x + 2 = -28 \]
\[ 10x + 2 - 2 = -28 - 2 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) + 2 = -30 + 2 = -28 \checkmark \]

Trying values of x in 10x + 2 = −28

x	10x + 2	Equals -28?
-5	-48	no
-4	-38	no
-3	-28	yes
-2	-18	no
-1	-8	no

Questions

What is x in 10x + 2 = −28?

The solution of 10x + 2 = −28 is x = -3.

How do you solve 10x + 2 = −28?

Subtract 2 from both sides to get 10x = -30, then divide both sides by 10 to get x = -3.

How do I check the answer?

Replace x by -3: 10(-3) + 2 = -28, which is -28.

Solve 10x + 2 = −28

How to work it out

Trying values of x in 10x + 2 = −28

Questions

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