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Solve 11x + 2 = āˆ’31

The solution of 11x + 2 = āˆ’31 is x = -3.

The lines y = 11x + 2 and y = -31 meet at x = -3-8-6-4-22-100-80-60-40-202040x = -3y = 11x + 2y = -31
The lines y = 11x + 2 and y = -31 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+2=āˆ’3111x + 2 = -31
  2. 2

    Subtract 2 from both sides:

    11x+2āˆ’2=āˆ’31āˆ’2 ⇒ 11x=āˆ’3311x + 2 - 2 = -31 - 2 \ \Rightarrow\ 11x = -33
  3. 3

    Divide both sides by 11:

    11x11=āˆ’3311 ⇒ x=āˆ’3\frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    11ā‹…(āˆ’3)+2=āˆ’33+2=āˆ’31āœ“11\cdot(-3) + 2 = -33 + 2 = -31 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 2 = -31\ \Rightarrow\ x = -3 \]
\[ 11x + 2 = -31 \]
\[ 11x + 2 - 2 = -31 - 2 \ \Rightarrow\ 11x = -33 \]
\[ \frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3 \]
\[ 11\cdot(-3) + 2 = -33 + 2 = -31 \checkmark \]

Trying values of x in 11x + 2 = āˆ’31

x11x + 2Equals -31?
-5-53no
-4-42no
-3-31yes
-2-20no
-1-9no

Questions

What is x in 11x + 2 = āˆ’31?

The solution of 11x + 2 = āˆ’31 is x = -3.

How do you solve 11x + 2 = āˆ’31?

Subtract 2 from both sides to get 11x = -33, then divide both sides by 11 to get x = -3.

How do I check the answer?

Replace x by -3: 11(-3) + 2 = -31, which is -31.

Similar equations

    Solve 11x + 2 = āˆ’31: x = -3 (steps and check) | WordGPT