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Solve 11x + 2 = āˆ’20

The solution of 11x + 2 = āˆ’20 is x = -2.

The lines y = 11x + 2 and y = -20 meet at x = -2-8-6-4-224-80-60-40-202040x = -2y = 11x + 2y = -20
The lines y = 11x + 2 and y = -20 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+2=āˆ’2011x + 2 = -20
  2. 2

    Subtract 2 from both sides:

    11x+2āˆ’2=āˆ’20āˆ’2 ⇒ 11x=āˆ’2211x + 2 - 2 = -20 - 2 \ \Rightarrow\ 11x = -22
  3. 3

    Divide both sides by 11:

    11x11=āˆ’2211 ⇒ x=āˆ’2\frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    11ā‹…(āˆ’2)+2=āˆ’22+2=āˆ’20āœ“11\cdot(-2) + 2 = -22 + 2 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 2 = -20\ \Rightarrow\ x = -2 \]
\[ 11x + 2 = -20 \]
\[ 11x + 2 - 2 = -20 - 2 \ \Rightarrow\ 11x = -22 \]
\[ \frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2 \]
\[ 11\cdot(-2) + 2 = -22 + 2 = -20 \checkmark \]

Trying values of x in 11x + 2 = āˆ’20

x11x + 2Equals -20?
-4-42no
-3-31no
-2-20yes
-1-9no
02no

Questions

What is x in 11x + 2 = āˆ’20?

The solution of 11x + 2 = āˆ’20 is x = -2.

How do you solve 11x + 2 = āˆ’20?

Subtract 2 from both sides to get 11x = -22, then divide both sides by 11 to get x = -2.

How do I check the answer?

Replace x by -2: 11(-2) + 2 = -20, which is -20.

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    Solve 11x + 2 = āˆ’20: x = -2 (steps and check) | WordGPT