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Solve 11x + 2 = āˆ’9

The solution of 11x + 2 = āˆ’9 is x = -1.

The lines y = 11x + 2 and y = -9 meet at x = -1-6-4-224-80-60-40-20204060x = -1y = 11x + 2y = -9
The lines y = 11x + 2 and y = -9 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+2=āˆ’911x + 2 = -9
  2. 2

    Subtract 2 from both sides:

    11x+2āˆ’2=āˆ’9āˆ’2 ⇒ 11x=āˆ’1111x + 2 - 2 = -9 - 2 \ \Rightarrow\ 11x = -11
  3. 3

    Divide both sides by 11:

    11x11=āˆ’1111 ⇒ x=āˆ’1\frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    11ā‹…(āˆ’1)+2=āˆ’11+2=āˆ’9āœ“11\cdot(-1) + 2 = -11 + 2 = -9 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 2 = -9\ \Rightarrow\ x = -1 \]
\[ 11x + 2 = -9 \]
\[ 11x + 2 - 2 = -9 - 2 \ \Rightarrow\ 11x = -11 \]
\[ \frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1 \]
\[ 11\cdot(-1) + 2 = -11 + 2 = -9 \checkmark \]

Trying values of x in 11x + 2 = āˆ’9

x11x + 2Equals -9?
-3-31no
-2-20no
-1-9yes
02no
113no

Questions

What is x in 11x + 2 = āˆ’9?

The solution of 11x + 2 = āˆ’9 is x = -1.

How do you solve 11x + 2 = āˆ’9?

Subtract 2 from both sides to get 11x = -11, then divide both sides by 11 to get x = -1.

How do I check the answer?

Replace x by -1: 11(-1) + 2 = -9, which is -9.

Similar equations

    Solve 11x + 2 = āˆ’9: x = -1 (steps and check) | WordGPT