Solve 10x + 2 = ā48
The solution of 10x + 2 = ā48 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 2 = -48\ \Rightarrow\ x = -5 \]
\[ 10x + 2 = -48 \]
\[ 10x + 2 - 2 = -48 - 2 \ \Rightarrow\ 10x = -50 \]
\[ \frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5 \]
\[ 10\cdot(-5) + 2 = -50 + 2 = -48 \checkmark \]Trying values of x in 10x + 2 = ā48
| x | 10x + 2 | Equals -48? |
|---|---|---|
| -7 | -68 | no |
| -6 | -58 | no |
| -5 | -48 | yes |
| -4 | -38 | no |
| -3 | -28 | no |
Questions
What is x in 10x + 2 = ā48?
The solution of 10x + 2 = ā48 is x = -5.
How do you solve 10x + 2 = ā48?
Subtract 2 from both sides to get 10x = -50, then divide both sides by 10 to get x = -5.
How do I check the answer?
Replace x by -5: 10(-5) + 2 = -48, which is -48.