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Solve 10x + 2 = āˆ’48

The solution of 10x + 2 = āˆ’48 is x = -5.

The lines y = 10x + 2 and y = -48 meet at x = -5-10-8-6-4-2-120-100-80-60-40-2020x = -5y = 10x + 2y = -48
The lines y = 10x + 2 and y = -48 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+2=āˆ’4810x + 2 = -48
  2. 2

    Subtract 2 from both sides:

    10x+2āˆ’2=āˆ’48āˆ’2 ⇒ 10x=āˆ’5010x + 2 - 2 = -48 - 2 \ \Rightarrow\ 10x = -50
  3. 3

    Divide both sides by 10:

    10x10=āˆ’5010 ⇒ x=āˆ’5\frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    10ā‹…(āˆ’5)+2=āˆ’50+2=āˆ’48āœ“10\cdot(-5) + 2 = -50 + 2 = -48 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 2 = -48\ \Rightarrow\ x = -5 \]
\[ 10x + 2 = -48 \]
\[ 10x + 2 - 2 = -48 - 2 \ \Rightarrow\ 10x = -50 \]
\[ \frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5 \]
\[ 10\cdot(-5) + 2 = -50 + 2 = -48 \checkmark \]

Trying values of x in 10x + 2 = āˆ’48

x10x + 2Equals -48?
-7-68no
-6-58no
-5-48yes
-4-38no
-3-28no

Questions

What is x in 10x + 2 = āˆ’48?

The solution of 10x + 2 = āˆ’48 is x = -5.

How do you solve 10x + 2 = āˆ’48?

Subtract 2 from both sides to get 10x = -50, then divide both sides by 10 to get x = -5.

How do I check the answer?

Replace x by -5: 10(-5) + 2 = -48, which is -48.

Similar equations

    Solve 10x + 2 = āˆ’48: x = -5 (steps and check) | WordGPT