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Solve 10x āˆ’ 2 = āˆ’42

The solution of 10x āˆ’ 2 = āˆ’42 is x = -4.

The lines y = 10x āˆ’ 2 and y = -42 meet at x = -4-10-8-6-4-22-100-80-60-40-2020x = -4y = 10x āˆ’ 2y = -42
The lines y = 10x āˆ’ 2 and y = -42 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’2=āˆ’4210x - 2 = -42
  2. 2

    Add 2 to both sides:

    10xāˆ’2+2=āˆ’42+2 ⇒ 10x=āˆ’4010x - 2 + 2 = -42 + 2 \ \Rightarrow\ 10x = -40
  3. 3

    Divide both sides by 10:

    10x10=āˆ’4010 ⇒ x=āˆ’4\frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    10ā‹…(āˆ’4)āˆ’2=āˆ’40āˆ’2=āˆ’42āœ“10\cdot(-4) - 2 = -40 - 2 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 2 = -42\ \Rightarrow\ x = -4 \]
\[ 10x - 2 = -42 \]
\[ 10x - 2 + 2 = -42 + 2 \ \Rightarrow\ 10x = -40 \]
\[ \frac{10x}{10} = \frac{-40}{10} \ \Rightarrow\ x = -4 \]
\[ 10\cdot(-4) - 2 = -40 - 2 = -42 \checkmark \]

Trying values of x in 10x āˆ’ 2 = āˆ’42

x10x āˆ’ 2Equals -42?
-6-62no
-5-52no
-4-42yes
-3-32no
-2-22no

Questions

What is x in 10x āˆ’ 2 = āˆ’42?

The solution of 10x āˆ’ 2 = āˆ’42 is x = -4.

How do you solve 10x āˆ’ 2 = āˆ’42?

Add 2 to both sides to get 10x = -40, then divide both sides by 10 to get x = -4.

How do I check the answer?

Replace x by -4: 10(-4) āˆ’ 2 = -42, which is -42.

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    Solve 10x āˆ’ 2 = āˆ’42: x = -4 (steps and check) | WordGPT