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One person does a job in 7 hours and another in 10 hours. How long together?

Working together they take 70/17 hours (about 4.1176471 hours, or 4 h 7 min).

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/7 of the job and the second does 1/10.

  2. 2

    Together in one hour they do the sum of the rates:

    17+110=10+770=1770\frac{1}{7} + \frac{1}{10} = \frac{10 + 7}{70} = \frac{17}{70}
  3. 3

    If they do 17/70 of the job per hour, the whole job takes the reciprocal:

    t=7017=7017≈4.1176471 hourst = \frac{70}{17} = \frac{70}{17} \approx 4.1176471\text{ hours}
  4. 4

    Check: that is less than 7 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{7} + \frac{1}{10} = \frac{1}{t}\ \Rightarrow\ t = \frac{70}{17} \]
\[ \frac{1}{7} + \frac{1}{10} = \frac{10 + 7}{70} = \frac{17}{70} \]
\[ t = \frac{70}{17} = \frac{70}{17} \approx 4.1176471\text{ hours} \]

Questions

How long do they take together?

Working together they take 70/17 hours (about 4.1176471 hours, or 4 h 7 min).

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    One job takes 7 hours and another 10: together 4.1176471 hours | WordGPT