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One person does a job in 7 hours and another in 7 hours. How long together?

Working together they take 7/2 hours (about 3.5 hours, or 3 h 30 min).

How to work it out

  1. 1

    Think in rates: in one hour the first does 1/7 of the job and the second does 1/7.

  2. 2

    Together in one hour they do the sum of the rates:

    17+17=7+749=1449\frac{1}{7} + \frac{1}{7} = \frac{7 + 7}{49} = \frac{14}{49}
  3. 3

    If they do 14/49 of the job per hour, the whole job takes the reciprocal:

    t=4914=72≈3.5 hourst = \frac{49}{14} = \frac{7}{2} \approx 3.5\text{ hours}
  4. 4

    Check: that is less than 7 hours, the faster worker alone, as it should be ✓

LaTeX source of the formulas on this page
\[ \frac{1}{7} + \frac{1}{7} = \frac{1}{t}\ \Rightarrow\ t = \frac{7}{2} \]
\[ \frac{1}{7} + \frac{1}{7} = \frac{7 + 7}{49} = \frac{14}{49} \]
\[ t = \frac{49}{14} = \frac{7}{2} \approx 3.5\text{ hours} \]

Questions

How long do they take together?

Working together they take 7/2 hours (about 3.5 hours, or 3 h 30 min).

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    One job takes 7 hours and another 7: together 3.5 hours | WordGPT