Solve x² + 8x + 7 = 0
The solutions of x² + 8x + 7 = 0 are x = -1 or x = -7.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 8, c = 7.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
Method 1, factoring. The roots are rational, so the left side factors:
- 5
A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:
- 6
Method 2, The quadratic formula works for every quadratic:
- 7
Simplify to get the solutions:
- 8
Check by putting x = -1 back in: a·x² + b·x + c = 1·(1) + 8·(-1) + 7 = 0 ✓
LaTeX source of the formulas on this page
\[ x^2 + 8x + 7 = 0\ \Rightarrow\ x = -1,\ -7 \]
\[ x^2 + 8x + 7 = 0 \]
\[ D = 8^2 - 4\cdot1\cdot7 = 64 - 28 = 36 \]
\[ \left(x + 1\right)\left(x + 7\right) = 0 \]
\[ x + 1 = 0 \Rightarrow x = -1\qquad x + 7 = 0 \Rightarrow x = -7 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{36}}{2} \]
\[ x = -1\quad\text{or}\quad x = -7 \]The parabola y = x² + 8x + 7
| x | y |
|---|---|
| -7 | 0 |
| -6 | -5 |
| -5 | -8 |
| -4 | -9 |
| -3 | -8 |
| -2 | -5 |
| -1 | 0 |
Questions
What are the solutions of x² + 8x + 7 = 0?
The solutions of x² + 8x + 7 = 0 are x = -1 or x = -7.
Does x² + 8x + 7 = 0 factor?
Yes: (x+1)(x+7) = 0.
What is the vertex of y = x² + 8x + 7?
(-4, -9). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -8, product = c/a = 7.