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Solve x² + 8x + 6 = 0

The solutions of x² + 8x + 6 = 0 are x = -4 + √10 or x = -4 - √10, that is x ≈ -0.83772234 and x ≈ -7.1622777.

x² +x += 0
x2+8x+6=0⇒x=−4+10, −4−10x^2 + 8x + 6 = 0 \Rightarrow x = -4 + \sqrt{10},\ -4 - \sqrt{10}
Discriminant D = 40 · x ≈ -0.837722, -7.16228

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 8x + 6-8-6-4-2-10-55101520x = -0.83772234x = -7.1622777vertexy = x² + 8x + 6
Graph of y = x² + 8x + 6. The curve crosses the x-axis at x = -0.83772234 and x = -7.1622777; the vertex is at (-4, -10).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 8, c = 6.

    x2+8x+6=0x^2 + 8x + 6 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅1⋅6=64−24=40D = 8^2 - 4\cdot1\cdot6 = 64 - 24 = 40
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±402x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{40}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+10orx=−4−10x = -4 + \sqrt{10}\quad\text{or}\quad x = -4 - \sqrt{10}
  6. 6

    As decimals: x ≈ -0.83772234 and x ≈ -7.1622777.

  7. 7

    Check numerically: for x ≈ -0.83772234 the left side is 8.8817842e-16 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 8x + 6 = 0\ \Rightarrow\ x = -4 + \sqrt{10},\ -4 - \sqrt{10} \]
\[ x^2 + 8x + 6 = 0 \]
\[ D = 8^2 - 4\cdot1\cdot6 = 64 - 24 = 40 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{40}}{2} \]
\[ x = -4 + \sqrt{10}\quad\text{or}\quad x = -4 - \sqrt{10} \]

The parabola y = x² + 8x + 6

xy
-7-1
-6-6
-5-9
-4-10
-3-9
-2-6
-1-1

Questions

What are the solutions of x² + 8x + 6 = 0?

The solutions of x² + 8x + 6 = 0 are x = -4 + √10 or x = -4 - √10, that is x ≈ -0.83772234 and x ≈ -7.1622777.

Does x² + 8x + 6 = 0 factor?

Not over the integers, because the discriminant 40 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 8x + 6?

(-4, -10). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8, product = c/a = 6.

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    Solve x² + 8x + 6 = 0: x = -4 + √10 or x = -4 - √10 (steps) | WordGPT