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Solve x² + 8x + 8 = 0

The solutions of x² + 8x + 8 = 0 are x = -4 + 2√2 or x = -4 - 2√2, that is x ≈ -1.1715729 and x ≈ -6.8284271.

x² +x += 0
x2+8x+8=0⇒x=−4+22, −4−22x^2 + 8x + 8 = 0 \Rightarrow x = -4 + 2\sqrt{2},\ -4 - 2\sqrt{2}
Discriminant D = 32 · x ≈ -1.17157, -6.82843

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² + 8x + 8-8-6-4-2-10-55101520x = -1.1715729x = -6.8284271vertexy = x² + 8x + 8
Graph of y = x² + 8x + 8. The curve crosses the x-axis at x = -1.1715729 and x = -6.8284271; the vertex is at (-4, -8).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 8, c = 8.

    x2+8x+8=0x^2 + 8x + 8 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅1⋅8=64−32=32D = 8^2 - 4\cdot1\cdot8 = 64 - 32 = 32
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±322x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{32}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+22orx=−4−22x = -4 + 2\sqrt{2}\quad\text{or}\quad x = -4 - 2\sqrt{2}
  6. 6

    As decimals: x ≈ -1.1715729 and x ≈ -6.8284271.

  7. 7

    Check numerically: for x ≈ -1.1715729 the left side is 8.8817842e-16 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 8x + 8 = 0\ \Rightarrow\ x = -4 + 2\sqrt{2},\ -4 - 2\sqrt{2} \]
\[ x^2 + 8x + 8 = 0 \]
\[ D = 8^2 - 4\cdot1\cdot8 = 64 - 32 = 32 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{32}}{2} \]
\[ x = -4 + 2\sqrt{2}\quad\text{or}\quad x = -4 - 2\sqrt{2} \]

The parabola y = x² + 8x + 8

xy
-71
-6-4
-5-7
-4-8
-3-7
-2-4
-11

Questions

What are the solutions of x² + 8x + 8 = 0?

The solutions of x² + 8x + 8 = 0 are x = -4 + 2√2 or x = -4 - 2√2, that is x ≈ -1.1715729 and x ≈ -6.8284271.

Does x² + 8x + 8 = 0 factor?

Not over the integers, because the discriminant 32 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 8x + 8?

(-4, -8). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8, product = c/a = 8.

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    Solve x² + 8x + 8 = 0: x = -4 + 2√2 or x = -4 - 2√2 (steps) | WordGPT