Solve 9x + 2 = ā43
The solution of 9x + 2 = ā43 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 2 = -43\ \Rightarrow\ x = -5 \]
\[ 9x + 2 = -43 \]
\[ 9x + 2 - 2 = -43 - 2 \ \Rightarrow\ 9x = -45 \]
\[ \frac{9x}{9} = \frac{-45}{9} \ \Rightarrow\ x = -5 \]
\[ 9\cdot(-5) + 2 = -45 + 2 = -43 \checkmark \]Trying values of x in 9x + 2 = ā43
| x | 9x + 2 | Equals -43? |
|---|---|---|
| -7 | -61 | no |
| -6 | -52 | no |
| -5 | -43 | yes |
| -4 | -34 | no |
| -3 | -25 | no |
Questions
What is x in 9x + 2 = ā43?
The solution of 9x + 2 = ā43 is x = -5.
How do you solve 9x + 2 = ā43?
Subtract 2 from both sides to get 9x = -45, then divide both sides by 9 to get x = -5.
How do I check the answer?
Replace x by -5: 9(-5) + 2 = -43, which is -43.