Solve 9x ā 2 = ā47
The solution of 9x ā 2 = ā47 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 2 to both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 9x - 2 = -47\ \Rightarrow\ x = -5 \]
\[ 9x - 2 = -47 \]
\[ 9x - 2 + 2 = -47 + 2 \ \Rightarrow\ 9x = -45 \]
\[ \frac{9x}{9} = \frac{-45}{9} \ \Rightarrow\ x = -5 \]
\[ 9\cdot(-5) - 2 = -45 - 2 = -47 \checkmark \]Trying values of x in 9x ā 2 = ā47
| x | 9x ā 2 | Equals -47? |
|---|---|---|
| -7 | -65 | no |
| -6 | -56 | no |
| -5 | -47 | yes |
| -4 | -38 | no |
| -3 | -29 | no |
Questions
What is x in 9x ā 2 = ā47?
The solution of 9x ā 2 = ā47 is x = -5.
How do you solve 9x ā 2 = ā47?
Add 2 to both sides to get 9x = -45, then divide both sides by 9 to get x = -5.
How do I check the answer?
Replace x by -5: 9(-5) ā 2 = -47, which is -47.