Solve 8x + 8 = ā64
The solution of 8x + 8 = ā64 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 8 = -64\ \Rightarrow\ x = -9 \]
\[ 8x + 8 = -64 \]
\[ 8x + 8 - 8 = -64 - 8 \ \Rightarrow\ 8x = -72 \]
\[ \frac{8x}{8} = \frac{-72}{8} \ \Rightarrow\ x = -9 \]
\[ 8\cdot(-9) + 8 = -72 + 8 = -64 \checkmark \]Trying values of x in 8x + 8 = ā64
| x | 8x + 8 | Equals -64? |
|---|---|---|
| -11 | -80 | no |
| -10 | -72 | no |
| -9 | -64 | yes |
| -8 | -56 | no |
| -7 | -48 | no |
Questions
What is x in 8x + 8 = ā64?
The solution of 8x + 8 = ā64 is x = -9.
How do you solve 8x + 8 = ā64?
Subtract 8 from both sides to get 8x = -72, then divide both sides by 8 to get x = -9.
How do I check the answer?
Replace x by -9: 8(-9) + 8 = -64, which is -64.