Solve 8x + 8 = ā56
The solution of 8x + 8 = ā56 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 8 = -56\ \Rightarrow\ x = -8 \]
\[ 8x + 8 = -56 \]
\[ 8x + 8 - 8 = -56 - 8 \ \Rightarrow\ 8x = -64 \]
\[ \frac{8x}{8} = \frac{-64}{8} \ \Rightarrow\ x = -8 \]
\[ 8\cdot(-8) + 8 = -64 + 8 = -56 \checkmark \]Trying values of x in 8x + 8 = ā56
| x | 8x + 8 | Equals -56? |
|---|---|---|
| -10 | -72 | no |
| -9 | -64 | no |
| -8 | -56 | yes |
| -7 | -48 | no |
| -6 | -40 | no |
Questions
What is x in 8x + 8 = ā56?
The solution of 8x + 8 = ā56 is x = -8.
How do you solve 8x + 8 = ā56?
Subtract 8 from both sides to get 8x = -64, then divide both sides by 8 to get x = -8.
How do I check the answer?
Replace x by -8: 8(-8) + 8 = -56, which is -56.