Solve 8x + 8 = ā48
The solution of 8x + 8 = ā48 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 8 = -48\ \Rightarrow\ x = -7 \]
\[ 8x + 8 = -48 \]
\[ 8x + 8 - 8 = -48 - 8 \ \Rightarrow\ 8x = -56 \]
\[ \frac{8x}{8} = \frac{-56}{8} \ \Rightarrow\ x = -7 \]
\[ 8\cdot(-7) + 8 = -56 + 8 = -48 \checkmark \]Trying values of x in 8x + 8 = ā48
| x | 8x + 8 | Equals -48? |
|---|---|---|
| -9 | -64 | no |
| -8 | -56 | no |
| -7 | -48 | yes |
| -6 | -40 | no |
| -5 | -32 | no |
Questions
What is x in 8x + 8 = ā48?
The solution of 8x + 8 = ā48 is x = -7.
How do you solve 8x + 8 = ā48?
Subtract 8 from both sides to get 8x = -56, then divide both sides by 8 to get x = -7.
How do I check the answer?
Replace x by -7: 8(-7) + 8 = -48, which is -48.