Solve 8x + 8 = ā72
The solution of 8x + 8 = ā72 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 8 = -72\ \Rightarrow\ x = -10 \]
\[ 8x + 8 = -72 \]
\[ 8x + 8 - 8 = -72 - 8 \ \Rightarrow\ 8x = -80 \]
\[ \frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10 \]
\[ 8\cdot(-10) + 8 = -80 + 8 = -72 \checkmark \]Trying values of x in 8x + 8 = ā72
| x | 8x + 8 | Equals -72? |
|---|---|---|
| -12 | -88 | no |
| -11 | -80 | no |
| -10 | -72 | yes |
| -9 | -64 | no |
| -8 | -56 | no |
Questions
What is x in 8x + 8 = ā72?
The solution of 8x + 8 = ā72 is x = -10.
How do you solve 8x + 8 = ā72?
Subtract 8 from both sides to get 8x = -80, then divide both sides by 8 to get x = -10.
How do I check the answer?
Replace x by -10: 8(-10) + 8 = -72, which is -72.