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Solve 8x + 4 = āˆ’28

The solution of 8x + 4 = āˆ’28 is x = -4.

The lines y = 8x + 4 and y = -28 meet at x = -4-10-8-6-4-22-80-60-40-2020x = -4y = 8x + 4y = -28
The lines y = 8x + 4 and y = -28 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+4=āˆ’288x + 4 = -28
  2. 2

    Subtract 4 from both sides:

    8x+4āˆ’4=āˆ’28āˆ’4 ⇒ 8x=āˆ’328x + 4 - 4 = -28 - 4 \ \Rightarrow\ 8x = -32
  3. 3

    Divide both sides by 8:

    8x8=āˆ’328 ⇒ x=āˆ’4\frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    8ā‹…(āˆ’4)+4=āˆ’32+4=āˆ’28āœ“8\cdot(-4) + 4 = -32 + 4 = -28 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 4 = -28\ \Rightarrow\ x = -4 \]
\[ 8x + 4 = -28 \]
\[ 8x + 4 - 4 = -28 - 4 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) + 4 = -32 + 4 = -28 \checkmark \]

Trying values of x in 8x + 4 = āˆ’28

x8x + 4Equals -28?
-6-44no
-5-36no
-4-28yes
-3-20no
-2-12no

Questions

What is x in 8x + 4 = āˆ’28?

The solution of 8x + 4 = āˆ’28 is x = -4.

How do you solve 8x + 4 = āˆ’28?

Subtract 4 from both sides to get 8x = -32, then divide both sides by 8 to get x = -4.

How do I check the answer?

Replace x by -4: 8(-4) + 4 = -28, which is -28.

Similar equations

    Solve 8x + 4 = āˆ’28: x = -4 (steps and check) | WordGPT