Solve 9x + 4 = ā32
The solution of 9x + 4 = ā32 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 4 = -32\ \Rightarrow\ x = -4 \]
\[ 9x + 4 = -32 \]
\[ 9x + 4 - 4 = -32 - 4 \ \Rightarrow\ 9x = -36 \]
\[ \frac{9x}{9} = \frac{-36}{9} \ \Rightarrow\ x = -4 \]
\[ 9\cdot(-4) + 4 = -36 + 4 = -32 \checkmark \]Trying values of x in 9x + 4 = ā32
| x | 9x + 4 | Equals -32? |
|---|---|---|
| -6 | -50 | no |
| -5 | -41 | no |
| -4 | -32 | yes |
| -3 | -23 | no |
| -2 | -14 | no |
Questions
What is x in 9x + 4 = ā32?
The solution of 9x + 4 = ā32 is x = -4.
How do you solve 9x + 4 = ā32?
Subtract 4 from both sides to get 9x = -36, then divide both sides by 9 to get x = -4.
How do I check the answer?
Replace x by -4: 9(-4) + 4 = -32, which is -32.