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Solve 8x + 4 = āˆ’20

The solution of 8x + 4 = āˆ’20 is x = -3.

The lines y = 8x + 4 and y = -20 meet at x = -3-8-6-4-22-60-40-2020x = -3y = 8x + 4y = -20
The lines y = 8x + 4 and y = -20 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+4=āˆ’208x + 4 = -20
  2. 2

    Subtract 4 from both sides:

    8x+4āˆ’4=āˆ’20āˆ’4 ⇒ 8x=āˆ’248x + 4 - 4 = -20 - 4 \ \Rightarrow\ 8x = -24
  3. 3

    Divide both sides by 8:

    8x8=āˆ’248 ⇒ x=āˆ’3\frac{8x}{8} = \frac{-24}{8} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    8ā‹…(āˆ’3)+4=āˆ’24+4=āˆ’20āœ“8\cdot(-3) + 4 = -24 + 4 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 4 = -20\ \Rightarrow\ x = -3 \]
\[ 8x + 4 = -20 \]
\[ 8x + 4 - 4 = -20 - 4 \ \Rightarrow\ 8x = -24 \]
\[ \frac{8x}{8} = \frac{-24}{8} \ \Rightarrow\ x = -3 \]
\[ 8\cdot(-3) + 4 = -24 + 4 = -20 \checkmark \]

Trying values of x in 8x + 4 = āˆ’20

x8x + 4Equals -20?
-5-36no
-4-28no
-3-20yes
-2-12no
-1-4no

Questions

What is x in 8x + 4 = āˆ’20?

The solution of 8x + 4 = āˆ’20 is x = -3.

How do you solve 8x + 4 = āˆ’20?

Subtract 4 from both sides to get 8x = -24, then divide both sides by 8 to get x = -3.

How do I check the answer?

Replace x by -3: 8(-3) + 4 = -20, which is -20.

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    Solve 8x + 4 = āˆ’20: x = -3 (steps and check) | WordGPT