Solve 8x + 12 = ā4
The solution of 8x + 12 = ā4 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 12 = -4\ \Rightarrow\ x = -2 \]
\[ 8x + 12 = -4 \]
\[ 8x + 12 - 12 = -4 - 12 \ \Rightarrow\ 8x = -16 \]
\[ \frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2 \]
\[ 8\cdot(-2) + 12 = -16 + 12 = -4 \checkmark \]Trying values of x in 8x + 12 = ā4
| x | 8x + 12 | Equals -4? |
|---|---|---|
| -4 | -20 | no |
| -3 | -12 | no |
| -2 | -4 | yes |
| -1 | 4 | no |
| 0 | 12 | no |
Questions
What is x in 8x + 12 = ā4?
The solution of 8x + 12 = ā4 is x = -2.
How do you solve 8x + 12 = ā4?
Subtract 12 from both sides to get 8x = -16, then divide both sides by 8 to get x = -2.
How do I check the answer?
Replace x by -2: 8(-2) + 12 = -4, which is -4.