Solve 8x + 12 = 4
The solution of 8x + 12 = 4 is x = -1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -1 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 12 = 4\ \Rightarrow\ x = -1 \]
\[ 8x + 12 = 4 \]
\[ 8x + 12 - 12 = 4 - 12 \ \Rightarrow\ 8x = -8 \]
\[ \frac{8x}{8} = \frac{-8}{8} \ \Rightarrow\ x = -1 \]
\[ 8\cdot(-1) + 12 = -8 + 12 = 4 \checkmark \]Trying values of x in 8x + 12 = 4
| x | 8x + 12 | Equals 4? |
|---|---|---|
| -3 | -12 | no |
| -2 | -4 | no |
| -1 | 4 | yes |
| 0 | 12 | no |
| 1 | 20 | no |
Questions
What is x in 8x + 12 = 4?
The solution of 8x + 12 = 4 is x = -1.
How do you solve 8x + 12 = 4?
Subtract 12 from both sides to get 8x = -8, then divide both sides by 8 to get x = -1.
How do I check the answer?
Replace x by -1: 8(-1) + 12 = 4, which is 4.