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Solve 8x āˆ’ 12 = āˆ’28

The solution of 8x āˆ’ 12 = āˆ’28 is x = -2.

The lines y = 8x āˆ’ 12 and y = -28 meet at x = -2-8-6-4-224-80-60-40-2020x = -2y = 8x āˆ’ 12y = -28
The lines y = 8x āˆ’ 12 and y = -28 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’12=āˆ’288x - 12 = -28
  2. 2

    Add 12 to both sides:

    8xāˆ’12+12=āˆ’28+12 ⇒ 8x=āˆ’168x - 12 + 12 = -28 + 12 \ \Rightarrow\ 8x = -16
  3. 3

    Divide both sides by 8:

    8x8=āˆ’168 ⇒ x=āˆ’2\frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    8ā‹…(āˆ’2)āˆ’12=āˆ’16āˆ’12=āˆ’28āœ“8\cdot(-2) - 12 = -16 - 12 = -28 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 12 = -28\ \Rightarrow\ x = -2 \]
\[ 8x - 12 = -28 \]
\[ 8x - 12 + 12 = -28 + 12 \ \Rightarrow\ 8x = -16 \]
\[ \frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2 \]
\[ 8\cdot(-2) - 12 = -16 - 12 = -28 \checkmark \]

Trying values of x in 8x āˆ’ 12 = āˆ’28

x8x āˆ’ 12Equals -28?
-4-44no
-3-36no
-2-28yes
-1-20no
0-12no

Questions

What is x in 8x āˆ’ 12 = āˆ’28?

The solution of 8x āˆ’ 12 = āˆ’28 is x = -2.

How do you solve 8x āˆ’ 12 = āˆ’28?

Add 12 to both sides to get 8x = -16, then divide both sides by 8 to get x = -2.

How do I check the answer?

Replace x by -2: 8(-2) āˆ’ 12 = -28, which is -28.

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    Solve 8x āˆ’ 12 = āˆ’28: x = -2 (steps and check) | WordGPT