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Solve 8x + 1 = āˆ’7

The solution of 8x + 1 = āˆ’7 is x = -1.

The lines y = 8x + 1 and y = -7 meet at x = -1-6-4-224-60-40-202040x = -1y = 8x + 1y = -7
The lines y = 8x + 1 and y = -7 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+1=āˆ’78x + 1 = -7
  2. 2

    Subtract 1 from both sides:

    8x+1āˆ’1=āˆ’7āˆ’1 ⇒ 8x=āˆ’88x + 1 - 1 = -7 - 1 \ \Rightarrow\ 8x = -8
  3. 3

    Divide both sides by 8:

    8x8=āˆ’88 ⇒ x=āˆ’1\frac{8x}{8} = \frac{-8}{8} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    8ā‹…(āˆ’1)+1=āˆ’8+1=āˆ’7āœ“8\cdot(-1) + 1 = -8 + 1 = -7 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 1 = -7\ \Rightarrow\ x = -1 \]
\[ 8x + 1 = -7 \]
\[ 8x + 1 - 1 = -7 - 1 \ \Rightarrow\ 8x = -8 \]
\[ \frac{8x}{8} = \frac{-8}{8} \ \Rightarrow\ x = -1 \]
\[ 8\cdot(-1) + 1 = -8 + 1 = -7 \checkmark \]

Trying values of x in 8x + 1 = āˆ’7

x8x + 1Equals -7?
-3-23no
-2-15no
-1-7yes
01no
19no

Questions

What is x in 8x + 1 = āˆ’7?

The solution of 8x + 1 = āˆ’7 is x = -1.

How do you solve 8x + 1 = āˆ’7?

Subtract 1 from both sides to get 8x = -8, then divide both sides by 8 to get x = -1.

How do I check the answer?

Replace x by -1: 8(-1) + 1 = -7, which is -7.

Similar equations

    Solve 8x + 1 = āˆ’7: x = -1 (steps and check) | WordGPT