Solve 8x + 1 = 1
The solution of 8x + 1 = 1 is x = 0.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 0 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 1 = 1\ \Rightarrow\ x = 0 \]
\[ 8x + 1 = 1 \]
\[ 8x + 1 - 1 = 1 - 1 \ \Rightarrow\ 8x = 0 \]
\[ \frac{8x}{8} = \frac{0}{8} \ \Rightarrow\ x = 0 \]
\[ 8\cdot0 + 1 = 0 + 1 = 1 \checkmark \]Trying values of x in 8x + 1 = 1
| x | 8x + 1 | Equals 1? |
|---|---|---|
| -2 | -15 | no |
| -1 | -7 | no |
| 0 | 1 | yes |
| 1 | 9 | no |
| 2 | 17 | no |
Questions
What is x in 8x + 1 = 1?
The solution of 8x + 1 = 1 is x = 0.
How do you solve 8x + 1 = 1?
Subtract 1 from both sides to get 8x = 0, then divide both sides by 8 to get x = 0.
How do I check the answer?
Replace x by 0: 8(0) + 1 = 1, which is 1.