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Solve 8x + 1 = āˆ’15

The solution of 8x + 1 = āˆ’15 is x = -2.

The lines y = 8x + 1 and y = -15 meet at x = -2-8-6-4-224-60-40-202040x = -2y = 8x + 1y = -15
The lines y = 8x + 1 and y = -15 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+1=āˆ’158x + 1 = -15
  2. 2

    Subtract 1 from both sides:

    8x+1āˆ’1=āˆ’15āˆ’1 ⇒ 8x=āˆ’168x + 1 - 1 = -15 - 1 \ \Rightarrow\ 8x = -16
  3. 3

    Divide both sides by 8:

    8x8=āˆ’168 ⇒ x=āˆ’2\frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    8ā‹…(āˆ’2)+1=āˆ’16+1=āˆ’15āœ“8\cdot(-2) + 1 = -16 + 1 = -15 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 1 = -15\ \Rightarrow\ x = -2 \]
\[ 8x + 1 = -15 \]
\[ 8x + 1 - 1 = -15 - 1 \ \Rightarrow\ 8x = -16 \]
\[ \frac{8x}{8} = \frac{-16}{8} \ \Rightarrow\ x = -2 \]
\[ 8\cdot(-2) + 1 = -16 + 1 = -15 \checkmark \]

Trying values of x in 8x + 1 = āˆ’15

x8x + 1Equals -15?
-4-31no
-3-23no
-2-15yes
-1-7no
01no

Questions

What is x in 8x + 1 = āˆ’15?

The solution of 8x + 1 = āˆ’15 is x = -2.

How do you solve 8x + 1 = āˆ’15?

Subtract 1 from both sides to get 8x = -16, then divide both sides by 8 to get x = -2.

How do I check the answer?

Replace x by -2: 8(-2) + 1 = -15, which is -15.

Similar equations

    Solve 8x + 1 = āˆ’15: x = -2 (steps and check) | WordGPT