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Solve 8x + 1 = āˆ’23

The solution of 8x + 1 = āˆ’23 is x = -3.

The lines y = 8x + 1 and y = -23 meet at x = -3-8-6-4-22-80-60-40-2020x = -3y = 8x + 1y = -23
The lines y = 8x + 1 and y = -23 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+1=āˆ’238x + 1 = -23
  2. 2

    Subtract 1 from both sides:

    8x+1āˆ’1=āˆ’23āˆ’1 ⇒ 8x=āˆ’248x + 1 - 1 = -23 - 1 \ \Rightarrow\ 8x = -24
  3. 3

    Divide both sides by 8:

    8x8=āˆ’248 ⇒ x=āˆ’3\frac{8x}{8} = \frac{-24}{8} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    8ā‹…(āˆ’3)+1=āˆ’24+1=āˆ’23āœ“8\cdot(-3) + 1 = -24 + 1 = -23 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 1 = -23\ \Rightarrow\ x = -3 \]
\[ 8x + 1 = -23 \]
\[ 8x + 1 - 1 = -23 - 1 \ \Rightarrow\ 8x = -24 \]
\[ \frac{8x}{8} = \frac{-24}{8} \ \Rightarrow\ x = -3 \]
\[ 8\cdot(-3) + 1 = -24 + 1 = -23 \checkmark \]

Trying values of x in 8x + 1 = āˆ’23

x8x + 1Equals -23?
-5-39no
-4-31no
-3-23yes
-2-15no
-1-7no

Questions

What is x in 8x + 1 = āˆ’23?

The solution of 8x + 1 = āˆ’23 is x = -3.

How do you solve 8x + 1 = āˆ’23?

Subtract 1 from both sides to get 8x = -24, then divide both sides by 8 to get x = -3.

How do I check the answer?

Replace x by -3: 8(-3) + 1 = -23, which is -23.

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    Solve 8x + 1 = āˆ’23: x = -3 (steps and check) | WordGPT