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Solve 8x + 1 = āˆ’31

The solution of 8x + 1 = āˆ’31 is x = -4.

The lines y = 8x + 1 and y = -31 meet at x = -4-10-8-6-4-22-80-60-40-2020x = -4y = 8x + 1y = -31
The lines y = 8x + 1 and y = -31 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+1=āˆ’318x + 1 = -31
  2. 2

    Subtract 1 from both sides:

    8x+1āˆ’1=āˆ’31āˆ’1 ⇒ 8x=āˆ’328x + 1 - 1 = -31 - 1 \ \Rightarrow\ 8x = -32
  3. 3

    Divide both sides by 8:

    8x8=āˆ’328 ⇒ x=āˆ’4\frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    8ā‹…(āˆ’4)+1=āˆ’32+1=āˆ’31āœ“8\cdot(-4) + 1 = -32 + 1 = -31 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 1 = -31\ \Rightarrow\ x = -4 \]
\[ 8x + 1 = -31 \]
\[ 8x + 1 - 1 = -31 - 1 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) + 1 = -32 + 1 = -31 \checkmark \]

Trying values of x in 8x + 1 = āˆ’31

x8x + 1Equals -31?
-6-47no
-5-39no
-4-31yes
-3-23no
-2-15no

Questions

What is x in 8x + 1 = āˆ’31?

The solution of 8x + 1 = āˆ’31 is x = -4.

How do you solve 8x + 1 = āˆ’31?

Subtract 1 from both sides to get 8x = -32, then divide both sides by 8 to get x = -4.

How do I check the answer?

Replace x by -4: 8(-4) + 1 = -31, which is -31.

Similar equations

    Solve 8x + 1 = āˆ’31: x = -4 (steps and check) | WordGPT