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Solve 8x āˆ’ 15 = āˆ’39

The solution of 8x āˆ’ 15 = āˆ’39 is x = -3.

The lines y = 8x āˆ’ 15 and y = -39 meet at x = -3-8-6-4-22-80-60-40-20x = -3y = 8x āˆ’ 15y = -39
The lines y = 8x āˆ’ 15 and y = -39 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’15=āˆ’398x - 15 = -39
  2. 2

    Add 15 to both sides:

    8xāˆ’15+15=āˆ’39+15 ⇒ 8x=āˆ’248x - 15 + 15 = -39 + 15 \ \Rightarrow\ 8x = -24
  3. 3

    Divide both sides by 8:

    8x8=āˆ’248 ⇒ x=āˆ’3\frac{8x}{8} = \frac{-24}{8} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    8ā‹…(āˆ’3)āˆ’15=āˆ’24āˆ’15=āˆ’39āœ“8\cdot(-3) - 15 = -24 - 15 = -39 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 15 = -39\ \Rightarrow\ x = -3 \]
\[ 8x - 15 = -39 \]
\[ 8x - 15 + 15 = -39 + 15 \ \Rightarrow\ 8x = -24 \]
\[ \frac{8x}{8} = \frac{-24}{8} \ \Rightarrow\ x = -3 \]
\[ 8\cdot(-3) - 15 = -24 - 15 = -39 \checkmark \]

Trying values of x in 8x āˆ’ 15 = āˆ’39

x8x āˆ’ 15Equals -39?
-5-55no
-4-47no
-3-39yes
-2-31no
-1-23no

Questions

What is x in 8x āˆ’ 15 = āˆ’39?

The solution of 8x āˆ’ 15 = āˆ’39 is x = -3.

How do you solve 8x āˆ’ 15 = āˆ’39?

Add 15 to both sides to get 8x = -24, then divide both sides by 8 to get x = -3.

How do I check the answer?

Replace x by -3: 8(-3) āˆ’ 15 = -39, which is -39.

Similar equations

    Solve 8x āˆ’ 15 = āˆ’39: x = -3 (steps and check) | WordGPT