Solve 8x ā 15 = ā47
The solution of 8x ā 15 = ā47 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 15 to both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 8x - 15 = -47\ \Rightarrow\ x = -4 \]
\[ 8x - 15 = -47 \]
\[ 8x - 15 + 15 = -47 + 15 \ \Rightarrow\ 8x = -32 \]
\[ \frac{8x}{8} = \frac{-32}{8} \ \Rightarrow\ x = -4 \]
\[ 8\cdot(-4) - 15 = -32 - 15 = -47 \checkmark \]Trying values of x in 8x ā 15 = ā47
| x | 8x ā 15 | Equals -47? |
|---|---|---|
| -6 | -63 | no |
| -5 | -55 | no |
| -4 | -47 | yes |
| -3 | -39 | no |
| -2 | -31 | no |
Questions
What is x in 8x ā 15 = ā47?
The solution of 8x ā 15 = ā47 is x = -4.
How do you solve 8x ā 15 = ā47?
Add 15 to both sides to get 8x = -32, then divide both sides by 8 to get x = -4.
How do I check the answer?
Replace x by -4: 8(-4) ā 15 = -47, which is -47.