Solve 9x ā 15 = ā42
The solution of 9x ā 15 = ā42 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 15 to both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 9x - 15 = -42\ \Rightarrow\ x = -3 \]
\[ 9x - 15 = -42 \]
\[ 9x - 15 + 15 = -42 + 15 \ \Rightarrow\ 9x = -27 \]
\[ \frac{9x}{9} = \frac{-27}{9} \ \Rightarrow\ x = -3 \]
\[ 9\cdot(-3) - 15 = -27 - 15 = -42 \checkmark \]Trying values of x in 9x ā 15 = ā42
| x | 9x ā 15 | Equals -42? |
|---|---|---|
| -5 | -60 | no |
| -4 | -51 | no |
| -3 | -42 | yes |
| -2 | -33 | no |
| -1 | -24 | no |
Questions
What is x in 9x ā 15 = ā42?
The solution of 9x ā 15 = ā42 is x = -3.
How do you solve 9x ā 15 = ā42?
Add 15 to both sides to get 9x = -27, then divide both sides by 9 to get x = -3.
How do I check the answer?
Replace x by -3: 9(-3) ā 15 = -42, which is -42.