Solve 9x + 15 = ā12
The solution of 9x + 15 = ā12 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 9:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 9x + 15 = -12\ \Rightarrow\ x = -3 \]
\[ 9x + 15 = -12 \]
\[ 9x + 15 - 15 = -12 - 15 \ \Rightarrow\ 9x = -27 \]
\[ \frac{9x}{9} = \frac{-27}{9} \ \Rightarrow\ x = -3 \]
\[ 9\cdot(-3) + 15 = -27 + 15 = -12 \checkmark \]Trying values of x in 9x + 15 = ā12
| x | 9x + 15 | Equals -12? |
|---|---|---|
| -5 | -30 | no |
| -4 | -21 | no |
| -3 | -12 | yes |
| -2 | -3 | no |
| -1 | 6 | no |
Questions
What is x in 9x + 15 = ā12?
The solution of 9x + 15 = ā12 is x = -3.
How do you solve 9x + 15 = ā12?
Subtract 15 from both sides to get 9x = -27, then divide both sides by 9 to get x = -3.
How do I check the answer?
Replace x by -3: 9(-3) + 15 = -12, which is -12.