Solve 7x + 1 = 43
The solution of 7x + 1 = 43 is x = 6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 6 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 1 = 43\ \Rightarrow\ x = 6 \]
\[ 7x + 1 = 43 \]
\[ 7x + 1 - 1 = 43 - 1 \ \Rightarrow\ 7x = 42 \]
\[ \frac{7x}{7} = \frac{42}{7} \ \Rightarrow\ x = 6 \]
\[ 7\cdot6 + 1 = 42 + 1 = 43 \checkmark \]Trying values of x in 7x + 1 = 43
| x | 7x + 1 | Equals 43? |
|---|---|---|
| 4 | 29 | no |
| 5 | 36 | no |
| 6 | 43 | yes |
| 7 | 50 | no |
| 8 | 57 | no |
Questions
What is x in 7x + 1 = 43?
The solution of 7x + 1 = 43 is x = 6.
How do you solve 7x + 1 = 43?
Subtract 1 from both sides to get 7x = 42, then divide both sides by 7 to get x = 6.
How do I check the answer?
Replace x by 6: 7(6) + 1 = 43, which is 43.