Solve 7x + 1 = 50
The solution of 7x + 1 = 50 is x = 7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = 7 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 1 = 50\ \Rightarrow\ x = 7 \]
\[ 7x + 1 = 50 \]
\[ 7x + 1 - 1 = 50 - 1 \ \Rightarrow\ 7x = 49 \]
\[ \frac{7x}{7} = \frac{49}{7} \ \Rightarrow\ x = 7 \]
\[ 7\cdot7 + 1 = 49 + 1 = 50 \checkmark \]Trying values of x in 7x + 1 = 50
| x | 7x + 1 | Equals 50? |
|---|---|---|
| 5 | 36 | no |
| 6 | 43 | no |
| 7 | 50 | yes |
| 8 | 57 | no |
| 9 | 64 | no |
Questions
What is x in 7x + 1 = 50?
The solution of 7x + 1 = 50 is x = 7.
How do you solve 7x + 1 = 50?
Subtract 1 from both sides to get 7x = 49, then divide both sides by 7 to get x = 7.
How do I check the answer?
Replace x by 7: 7(7) + 1 = 50, which is 50.